Question

How to solve 14 (4-x) + 7 (x-4) 27? ​

Answer 1

Step-by-step explanation:

$14(4-x)+7(x-4)27$

$56-14x+7\left(x-4\right)\times 27$

$56-14x+189\left(x-4\right)$

$56-14x+189x-756$

$56+175x-756$

$-700+175x$

hope it helps

Answer 2

Answer:

Answer is

Step-by-step explanation:

14(4−x)+7(x−4)27

56-14x+7\left(x-4\right)\times 2756−14x+7(x−4)×27

56-14x+189\left(x-4\right)56−14x+189(x−4)

56-14x+189x-75656−14x+189x−756

56+175x-75656+175x−756

-700+175x−700+175x