Question

how to solve 16/4-root32

Answer 1

Hey dear!


Here is yr answer......

$= > \frac{16}{4 - \sqrt{32} } \\ \\ on \: rationlising......... \\ \\ = > \frac{16}{4 - \sqrt{32} } \times \frac{4 + \sqrt{32} }{4 + \sqrt{32} } \\ \\ = > \frac{16(4 + \sqrt{32} ) }{16 - 32} \\ \\ = > \frac{16(4 + \sqrt{32}) }{ - 16} \\ \\ = > - 1(4 + \sqrt{32} ) \\ \\ = > - 4 - \sqrt{32}$


Hope it hlpz...

Answer 2

sqrt(x+32)-sqrt(x-16)=4
One solution was found :
x = 32
Radical Equation entered :
√x+32-√x-16 = 4


Step by step solution :
Step 1 :
Isolate a square root on the left hand side :
Original equation
√x+32-√x-16 = 4

Isolate
√x+32 = √x-16+4


Step 2 :
Eliminate the radical on the left hand side :
Raise both sides to the second power
(√x+32)2 = (√x-16+4)2

After squaring
x+32 = x-16+16+8√x-16


Step 3 :
Get remaining radical by itself :
Current equation
x+32 = x-16+16+8√x-16

Isolate radical on the left hand side
-8√x-16 = -x-32+x-16+16

Tidy up
8√x-16 = 32


Step 4 :
Eliminate the radical on the left hand side :
Raise both sides to the second power
(8√x-16)2 = (32)2

After squaring
64x-1024 = 1024


Step 5 :
Solve the linear equation :
Rearranged equation
64x -2048 = 0

Add 2048 to both sides
64x = 2048

Divide both sides by 64
A possible solution is :
x = 32

Step 6 :
Check that the solution is correct :
Original equation, root isolated, after tidy up
√x+32 = √x-16+4

Plug in 32 for x
√(32)+32 = √(32)-16+4

Simplify
√64 = 8
Solution checks !!
Solution is:
x = 32

One solution was found :
x = 32