Question

How to solve: (2^5+2^8)×2^-7

Answer 1

$\huge\underline{\bf \orange{Solution :}}$

$\implies \sf ( {2}^{5} + {2}^{8} ) \times {2}^{ -7} \\ \\\implies \sf (256 + 32) \times \frac{1}{{2}^{7} }\\ \\\implies \sf 288 \times \frac{1}{ {2}^{7}} \\\\\implies \sf 288 \times \frac{1}{128} \\ \\\implies\underline { \boxed{ \sf 2.25}}$

Answer 2

Step-by-step explanation:

$( {2}^{5} + {2}^{8} ) \times {2}^{ - 7}$

$32 + 256 \times { \frac{1}{2^7} }$

$288 \times { \frac{1}{2^7} }$

from here u try.....✌️u will find ur ans...✌️