Math, asked by rahulchauhan6832, 4 days ago

how to solve 2^5×4^2×27^3 by 2^2×3^5

Answers

Answered by dayanidhisharma19
0

Answer:

The answer is 10,368

Step-by-step explanation:

2^5×4^2×27^3 by 2^2×3^5

=(2^5×4^2×27^3) /(2^2×3^5)

=(2^5×(2^2) ^2×(3^3) ^3) /(2^2×3^5)

=(2^5×2^4×3^9) /(2^2×3^5)

=(2^9×3^9) /(2^2×3^5)

=2^(9-2) ×3^(9-5) =2^7×3^4 = 128×81=10,368

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