how to solve 2 sin48° cos12°?
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For this u can follow the following formula:
2sinAcosB= sin(A+B) + sin(A-B)
In this question we have ,
2sin48°cos12°
=sin(48°+12°) + sin(40°-12°)
=sin60°+sin26°
=1/√2+sin26°
you can leave the answer like this or use a calculator to find the value of sin26° . you cannot find the value of sin26° manually as 26° not one of the standard angles.
if you do use the calculator to find the value of sin26° , the value should be 0.438.
therefore ur answer should be
1/1.414+ 0.438
=0.707+ 0.438
=1.145
hope u find this helpful :)
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