Question

How to solve
216a^3 -2 root 2 b^3
Plz help

Answer 1

216 = 6^3.
2√2 = (√2)^3.
So the given equation becomes
(6a)^3 - (√2b)^3 .
Using identity a^3 -b^3 = (a - b)(a^2 +b^2 + 2ab).
We get
(6a -√2b)(36a^2 +2b^2 + 12√2ab).
Hope you understood my answer. If yes then plz mark me as the brainliest.
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Answer 2

Answer:

( 6 a )³ - ( √2 b )³ = ( 6 a - √2 b )( 36 a² + 2 b² + 6 √2 a b )

Step-by-step explanation:

216 a³ - 2 √2 b³

This can be re written as:

= ( 6 )³ a³ - ( √2 )³ b³

= ( 6 a )³ - ( √2 b )³

Using the identity:  x³ - y³ = ( x - y )( x² + y² + x y ), we get that:

( 6 a )³ - ( √2 b )³ = ( 6 a - √2 b )( (6 a)² + (√2 b)² + (6 a) (√2 b) )

( 6 a )³ - ( √2 b )³ = ( 6 a - √2 b )( 36 a² + 2 b² + 6 √2 a b )

Therefore, we get that ( 6 a )³ - ( √2 b )³ is equal to ( 6 a - √2 b )( 36 a² + 2 b² + 6 √2 a b ).

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