Question

how to solve 27/125^2/3*9/25^-3/2

Answer 1

Hope it helps you brother.

This is absolutely correct answer brother.

Answer 2

The correct answer is $\frac{5}{3}$.

Given: The equation = $\frac{27}{125}^{\frac{2}{3} } \frac{9}{25} ^{\frac{-3}{2} }$.

To Find: Evaluate the equation.

Solution:

$\frac{27}{125}^{\frac{2}{3} } \frac{9}{25} ^{\frac{-3}{2} }$

To remove the negative sign do the reciprocal of base.

= $\frac{27}{125}^{\frac{2}{3} } \frac{25}{9} ^{\frac{3}{2} }$

= $\frac{27}{125}^{\frac{2}{3} } \frac{25}{9} ^{\frac{1}{2} *3}$

= $\frac{27}{125}^{\frac{2}{3} } \frac{5}{3} ^{3}$

= $\frac{27}{125}^{\frac{1}{3} *2} \frac{5}{3} ^{3}$

= $\frac{3}{5}^2 \frac{5}{3} ^{3}$

= $\frac{3}{5}^2 \frac{3}{5} ^{-3}$

As the base is same powers can be added and subtracted.

= $(\frac{3}{5})^-1$

= $\frac{5}{3}$

Hence, the answer is $\frac{5}{3}$.

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