Question

how to solve : (2a-3b)×(2a+3b)​

Answer 1

Answer:

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Answer 2

Answer:

The given polynomials are 2a+3b and 2a−3b we multiply them as follows:

(2a+3b)(2a−3b)=(2a×2a)+(2a×−3b)+(3b×2a)+(3b×−3b)=4a^2−6ab+6ab−9b^2=4a^2 −9b ^2

Hence, (2a+3b)(2a−3b)=4a ^2 −9b ^2

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