Math, asked by sintu55, 1 year ago

how to solve (2x-y+3)(2x-y-3)​

Answers

Answered by Anonymous
74

Answer:

{(2x-y)+3}{(2x-y) - 3}

{(2x-y)^2 - 3^2}

{4x^2 +y^2 -4xy -9 }

This is the answer :)


memzovaload: Hi
Answered by aaruhisharma35
11

Answer:

Let 2x-3y=a Then

given= (a+5) (a-5) = a^2 -5^2= a- 25

= (2x-3y)^2 -25

= (2x)^2 -2 (2x) (3y) + (3y)^2 -25

= 4x^2 -12xy + 9y^2 -25.

hope it helps u!

Similar questions