Question

how to solve 3-√7/3-√7​

Answer 1

Answer:

On simplifying,

3−73+7=a+b7

⇒3−73+7×3+73+7=a+b7

⇒32−(7)2(3+7)2=a+b7

⇒29+7+67=a+7

⇒216+67=a+7

⇒22

Answer 2

Answer:

So U can recheck your question ..

Step-by-step explanation:

Since both Numerator and Denominator Is same therefore it will Cancelled

and If

it's 3+√7 on Numerator

It will be

$\binom{3 + \sqrt{7} }{3 - \sqrt{7} } = \binom{3 + \sqrt{7} }{3 - \sqrt{7} } \times \binom{3 + \sqrt{7} }{3 + \sqrt{7} }$

$\binom{ {(3 + \sqrt{7} )}^{2} }{ {3}^{2} - { \sqrt{7} }^{2} } = \binom{9 + 7 + 6 \sqrt{3} }{9 - 7}$

$\binom{2(5 + 3 \sqrt{7}) }{2}$

$= 5 + 3 \sqrt{7}$

PLS MARK AS BRANLIEST

Itz

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