Question

how to solve 3 upon root 3 + root 5 minus root 2

Answer 1

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Answer 2

Answer:

$\frac{3}{\sqrt{3}}+\sqrt{5}-\sqrt{2}=\sqrt{3}+\sqrt{5}-\sqrt{2}$

Step-by-step explanation:

Given Expression , $\frac{3}{\sqrt{3}}+\sqrt{5}-\sqrt{2}$

We have to simplify it

Consider,

$\frac{3}{\sqrt{3}}+\sqrt{5}-\sqrt{2}$

Rationalize the denominator of first term,

$\frac{3}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}}+\sqrt{5}-\sqrt{2}$

$\implies\frac{3\sqrt{3}}{(\sqrt{3})^2}+\sqrt{5}-\sqrt{2}$

$\implies\frac{3\sqrt{3}}{3}+\sqrt{5}-\sqrt{2}$

$\implies\sqrt{3}+\sqrt{5}-\sqrt{2}$

Therefore, $\frac{3}{\sqrt{3}}+\sqrt{5}-\sqrt{2}=\sqrt{3}+\sqrt{5}-\sqrt{2}$