Question

how to solve 3ax+28by+4ay+21bx

Answer 1

Answer:

$(7b + a)(3x + 4y)$

Step-by-step explanation:

As the equation is,

3ax +28by +4ay +21bx

so we will first separate the common one's,

3ax , 4ay and 28by, 21bx

Now we have to just factorise,

$a(3x + 4y) + 7b(3x + 4y)$

$= (7b + a)(3x + 4y)$

which is your answer.

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