how to solve 4√28÷4√16
Answers
Answer:
x⁴ - 4 x³ y√3 + 6 x² * 3 y² - 4 x y³ 3√3 + 9 y⁴ = 28 - 16 √3 x⁴ + 18 x²y² + 9 y⁴ = 28 -- equation 1 x² y + 3 x y² = 4 -- equation 2. Solve
Explanation:
2.67 is the value of 4 \sqrt{28} \div 3 \sqrt{7}428÷37
To find:
The value of 4 \sqrt{28} \div 3 \sqrt{7}428÷37
Solution:
We have to find the value of 4 \sqrt{28} \div 3 \sqrt{7}428÷37 So first we need to expand the values within the square root and then the square numbers can be taken out and then the equation becomes simplified.
=\frac{4 \sqrt{28}}{3 \sqrt{7}}=37428
=\frac{4 \sqrt{4 \times 7}}{3 \sqrt{7}}=3744×7
As we know that the value of,
[Since, the square root value of 4 is 2]
=\frac{4 \times 2 \sqrt{7}}{3 \sqrt{7}}=374×27
=\frac{8 \sqrt{7}}{3 \sqrt{7}}=3787
\sqrt{7}7 in the denominator and the numerator place can be cancelled each other.
Therefore,the above equation becomes
=\frac{8}{3}=38
=2.67
Hence the value of 4 \sqrt{28} \div 3 \sqrt{7}428÷37 is 2.67