how to solve -4* root2/root3
Answers
Answered by
0
Answer:
(
3
−
2
)
2
=5−2
6
Step-by-step explanation:
Given : Expression (\sqrt{3}-\sqrt{2})^2(
3
−
2
)
2
To find : Simplify the expression ?
Solution :
Applying algebraic identity,
(a-b)^2=a^2+b^2-2ab(a−b)
2
=a
2
+b
2
−2ab
Here, a=\sqrt{3}a=
3
and b=\sqrt{2}b=
2
Substitute the value,
(\sqrt{3}-\sqrt{2})^2=(\sqrt{3})^2+(\sqrt{2})^2-2\times (\sqrt{3})\times (\sqrt{2})(
3
−
2
)
2
=(
3
)
2
+(
2
)
2
−2×(
3
)×(
2
)
(\sqrt{3}-\sqrt{2})^2=3+2-2\sqrt{6}(
3
−
2
)
2
=3+2−2
6
(\sqrt{3}-\sqrt{2})^2=5-2\sqrt{6}(
3
−
2
)
2
=5−2
6
#Learn more
Simplify (2+root3) (2-root3)
Step-by-step explanation:
please mark me as brainliest answer
Similar questions