Math, asked by victoriarajputpda9y6, 1 year ago

how to solve (4a-3b)³

Answers

Answered by aqibkincsem
0

Formula to be used: 

(a−b)2=a2+b2−2∗a∗b(a−b)2=a2+b2−2∗a∗b; (3b−4a)(3b−4a)(3b−4a)(3b−4a)=(3b−4a)2=(3b−4a)2=(3b)2+(4a)2−(2∗3b∗4a)=(3b)2+(4a)2−(2∗3b∗4a)=9b2+16a2−24ab.

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