Math, asked by ParthDeshmane, 1 year ago

how to solve 4m+6n=54;3m+2n=28

Answers

Answered by guptasidd1707
1
m =( 54- 6n)/4

3m + 2n =28

3(54-6n)/4 + 2n = 28

162 - 18n + 8n = 84

10n = 78
n = 78/10

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guptasidd1707: tu
Answered by chemistrywala
0
multiplying the second equation by 3, we get 4m+6n=54---(1) and 9m+6n =84 subtracting eq.2 from eq1 we get 5n =30 n=6 and m= 16/3
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