Question

how to solve 4r²^a + 12r^a s^b + 9s²^b​

Answer 1

Answer:

here's your answer dear

the question is the only answer because after rearranging we cannot simplify further.

hope it helps you from my side

Answer 2

Answer:

Given x

2

−7x+12=0

This is in the form ax

2

+bx+c=0 where, a = 1, b = -7 and c = 12

Quadratic formula is, x=

2a

−b±

b

2

−4ac

By substituting the values, we get

x=

2×1

−(−7)±

(−7)

2

−4×1×12

=

2

7±

49−48

=

2

7±

1

=

2

7±1

If x=

2

7+1

=

2

8

=4 x=

2

7−1

=

2

6

=3

∴ 4 and 3 are the roots of x

2

−7x+12=0