how to solve 4x²-4ax+(a²-b²)=0 ?
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4x²-4ax +(a²-b²)=0
4x²-2(a+b) x-2(a-b)x +(a+b)(a-b)=0
⇒2x[2x-(a+b)] -(a-b)[2x-(a+b)]=0
⇒[2x-(a+b)] [2x-(a-b)]=0
therefore
2x-(a+b) =0 or 2x-(a-b) =0
2x = (a+b) or 2x= (a-b)
x= (a+b)/2 or x= (a-b) /2
4x²-2(a+b) x-2(a-b)x +(a+b)(a-b)=0
⇒2x[2x-(a+b)] -(a-b)[2x-(a+b)]=0
⇒[2x-(a+b)] [2x-(a-b)]=0
therefore
2x-(a+b) =0 or 2x-(a-b) =0
2x = (a+b) or 2x= (a-b)
x= (a+b)/2 or x= (a-b) /2
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