How to solve 5 cm 6 cm and 10 cm to form a triangle by three lines segments 
Answers
Answer:
on first line of triangle write 5 cm nd in sec. line write 6 cm. nd in 3rd line write 10 cm at below
Step-by-step explanation:
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Answer:
A)
Steps of Construction for triangle:
1. Draw a line segment BC of length 5cm.
2. Measure distance of 6 cm in compass. Taking B as centre draw an arc.
3. Taking C as centre with same distance and draw another arc.
4. Both the arcs intersect each other; name that point of intersection as A.
5. Required triangle ABC is drawn.
Area of ABC can be calculated using Heron's formula.
s= 2/5+6+6 = 2/17 cm
Area △ABC= 2/1 ( 2/17 −5)( 2/17 −6( /17 −6)= 2/17 × 2/7 × 2/5 × 2/5 =13.6cm
2
Area of Square =(side) ^
13.63=(side) ^
side=3.7cm
(B)
Steps of Construction for square:
1.Draw segment BC of length 3.7cm.
2.Draw a line perpendicular to BC through B.
Measure a distance of 3.7 cm in compass and cut this line at point A.
3.Draw a line perpendicular to BC through C.
Measure a distance of 3.7 cm in compass and cut this line at point D.
4.Join AB, CD and AD.
5.Required square ABCD is drawn.
