Question

How to solve 5 m square + 2 m+ 1 equals to zero by completing the square method

Answer 1

Answer:

$5 {x}^{2} + 2x + 1 = 0$

$( \sqrt{5} x) {}^{2} + 2 \times \sqrt{5} x \times \frac{1}{ \sqrt{5} } + ( { \frac{1}{ \sqrt{5} }) }^{2} + 1 - ( { \frac{1}{ \sqrt{5} }) }^{2} = 0$

$( { \sqrt{5}x + \frac{1}{ \sqrt{5} }) }^{2} + 1 - \frac{1}{5} = 0$

$( { \sqrt{5} x + \frac{1}{ \sqrt{5} }) }^{2} = - \frac{4}{5}$

$\sqrt{5} x + \frac{1}{ \sqrt{5} } = \frac{2}{ \sqrt{5} } i \: \: \: or \: - \frac{2}{ \sqrt{5} } i$

$\sqrt{5} x = \frac{ - 1 + 2i}{ \sqrt{5} } \: \: \: or \: \: \: \frac{ - 1 - 2i}{ \sqrt{5} }$

Mark BRAINLIEST if you think. Thanks