How to solve: 52^3 - 32^3 - 20^3
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if a+b+c=0 then
a^3+b^3+c^3=3abc
here a=52,b=-32,c= -20
a+b+c=52-32-20=0
therefore
52^3+(-32)^3+(-20)^3=3*52*(-32)*(-20)
=99840
a^3+b^3+c^3=3abc
here a=52,b=-32,c= -20
a+b+c=52-32-20=0
therefore
52^3+(-32)^3+(-20)^3=3*52*(-32)*(-20)
=99840
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