Math, asked by Adityanegi627, 1 year ago

How to solve 7^2.3 * 49^4.7 * 63^3.4 * 81^5.85 = 63^?

Answers

Answered by harikrishna6224
1

Step-by-step explanation:

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Answered by FelisFelis
1

The value required value is 15.1

Step-by-step explanation:

Consider the provided expression.

7^{2.3} \times 49^{4.7} \times 63^{3.4}\times81^{5.85} = 63^?

Rewrite the equation as shown:

7^{2.3} \times (7\times7)^{4.7} \times (7\times9)^{3.4}\times(9\times9)^{5.85} = 63^?

7^{2.3} \times 7^{4.7+4.7} \times 7^{3.4}\times9^{3.4}\times9^{5.85+5.85}= 63^?

7^{2.3} \times 7^{9.4} \times 7^{3.4}\times9^{3.4}\times9^{11.7}= 63^?

7^{(2.3+9.4+3.4)}\times9^{(3.4+11.7)}= 63^?

7^{15.1}\times9^{15.1}= 63^?

63^{15.1}= 63^?

Hence, the value required value is 15.1

#Learn more

All rules of exponent

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