Question

how to solve 7^x = 2^4 ÷ 4^2
step-by-step explanation

Answer 1

Step-by-step explanation:

Solution :-

Given that

7^x = 2^4 ÷ 4^2

=> 7^x = 2^4 ÷ (2^2)^2

=> 7^x = 2^4 ÷ 2^4

Since (a^m)^n = a^(mn)

=> 7^x = 1

=> 7^x = 7^0

Since , a^0 = 1

We know that

If bases are equal then exponents must be equal.

=> x = 0

Therefore, x = 0

Answer:-

The value of x is 0

Check:-

If x = 0 then LHS of the given equation

=> 7^0 = 1

RHS = 2^4÷4^2

=> 2^4÷2^4

=> 1

=> LHS = RHS is true for x = 0

Used formulae:-

→ (a^m)^n = a^(mn)

→ a^0 = 1

→ If a^m = a^n => m = n

Answer 2

Answer:

x=0

Step-by-step explanation:

as

$7 {}^{ x} = {2}^{4} \div {4}^{2} = 16 \div 16 = 1$

any number to the power zero is 1

therefore the solution to the question is x=0