Question

how to solve ................................​

Answer 1

Answer:

5

Step-by-step explanation:

Given $\frac{5y-3}{y}+$$\frac{5x-3}{x}$+$\frac{5z-3}{z}$=0

Now break the term separetly we'll get:

5-$\frac{3}{x}$+5-$\frac{3}{y}$+5$\frac{3}{y}$=0

⇒15-3($\frac{1}{x}$+$\frac{1}{y}$+$\frac{1}{z}$)=0

⇒$\frac{1}{x}$+$\frac{1}{y}$+$\frac{1}{z}$=15/3=5