how to solve a^3-2a^2-a+2=0
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a³ - 2a²-a +2= 0
=> a²(a - 2) - 1(a-2) = 0
=> (a - 2)(a² - 1) = 0
either a- 2 = 0 or a² -1 =0
=> a = 2 or a = 1
Therefore,
a = 2 or 1
=> a²(a - 2) - 1(a-2) = 0
=> (a - 2)(a² - 1) = 0
either a- 2 = 0 or a² -1 =0
=> a = 2 or a = 1
Therefore,
a = 2 or 1
kovvadasriramulu:
-1also
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