how to solve a problem of quadratic expressions which have power of 2/3
Answers
Answered by
1
According to the standard on polynomials, you can’t have a coefficient of something that isn’t a whole number on a variable. However this is breached in solving quadratic equations and so I’ll assume it is important to know.
Assume you have a number, say 2
In the question you see 2 to the power of 2/3.
For the purpose of understanding, let’s take 2/3=m/n
Now we have 2^2\3, which we’re going to express as 2^m/n
To express it without a power,
Nth root of number raised to M
So, cube root of (2)^2
Hope I could help!
Assume you have a number, say 2
In the question you see 2 to the power of 2/3.
For the purpose of understanding, let’s take 2/3=m/n
Now we have 2^2\3, which we’re going to express as 2^m/n
To express it without a power,
Nth root of number raised to M
So, cube root of (2)^2
Hope I could help!
Similar questions