Question

How to solve a qaydratic eqaution by completing square method

Answer 1

What you have to do is to follow the format
ax^2+bx+c=0
→x^2+(b/a)x+c/a=0
x^2+2(b/2a)x+(b/2a)^2-(b/2a)^2+c/a=0
→[x^2+2(b/2a)+(b/2a)^2]=(b/2a)^2-c/a

Using x^2+y^2 +2xy=(x+y) ^2

→[x+(b/2a)]^2=(b/2a)^2 - c/a
=(b^2)/4(a^2)-c/a
=(b^2-4ac)/4(a^2)

So x= [- b±√(b^2-4ac)]/2a

So what u have to do is to just make down quadratic formula

Hope it was easy for you