Math, asked by JAGAJEETH, 1 year ago

How to solve a quadratic equation by squaring?

raoatchut191: by squaring??????????

JAGAJEETH: yes

kaushikravikant: by squaring means

JAGAJEETH: Divide through by whatever is multiplied on the squared term. Take half of the coefficient (don't forget the sign!) of the x-term, and square it. Add this square to both sides of the equation. Convert the left-hand side to squared form, and simplify the right-hand side.

kaushikravikant: bhai,jab pataa hai to puch kyon raha rah

JAGAJEETH: this is an information in google

JAGAJEETH: but still i dont know

kaushikravikant: Ask your teacher,he/she will better teach you

Answers

Answered by GowriShankar

Algorithm : Let the quadratic equation by ax2 + bx + c = 0
Step-1 : Divide each side by ‘a’
Step-2 : Rearrange the equation so that constant term c/a is on the right side. (RHS)
Step-3 : Add (1/2×b/a)^2 to both sides to make LHS, a perfect square
.Step-4 : Write the LHS as a square and simplify the RHS.
Step-5 : Solve it.
^2menas raised to power

JAGAJEETH: what means ^

GowriShankar: ^ this means the symbol of exponent

raoatchut191: it means "to the power of"

Answered by shivam2000

First make the square term a perfect term either by dividing or by multiplying.
Then try to make the equation in the form of a²+b²+2ab or a²+b²-2ab.
You can make it by consider an example
ax²+bx+c=0, here a is not equals to 0

Dividing whole equation by a, we get

x²+bx + c = 0
a a
x²+bx = - c
a a
adding (b )² to both sides
(2a)
x²+bx + (b)² = - c + ( b)²
a (2a) a (2a)

(x+ b)² = -c + b²
( 2a) a 4a²
(x+b)² = b²-4ac
( 2a) 4a²

x+b = + and - √b²-4ac
2a 2a

x= -b +√ b²-4ac
2a
OR

x= -b -√ b²-4ac
2a

raoatchut191: hey u r the best frnd of tps right??

shivam2000: no

GowriShankar: about r u sying raoatchut

raoatchut191: im saying abt tarun

GowriShankar: kkkkkkkkk

raoatchut191: but i asked abt it to shivam

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