Question

How to solve algebraic geometry

Answer 1

✨Hi mate..✨

Hope this helps you...

✨The fact that the field of the real numbers is an ordered field cannot be ignored in such a study. For example, the curve of equation {\displaystyle x^{2}+y^{2}-a=0}is a circle if {\displaystyle a>0}, but does not have any real point if {\displaystyle a<0}. It follows that real algebraic geometry is not only the study of the real algebraic varieties, but has been generalized to the study of the semi-algebraic sets, which are the solutions of systems of polynomial equations and polynomial inequalities. For example, a branch of the hyperbolaof equation {\displaystyle xy-1=0} is not an algebraic variety, but is a semi-algebraic set defined by {\displaystyle xy-1=0} and {\displaystyle x>0}or by {\displaystyle xy-1=0}and {\displaystyle x+y>0}.✨