how to solve algeric
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Solve an algebraic expression with fractions.
(x + 3)/6 = 2/3. First, cross multiply to get rid of the fraction. ...(x + 3) x 3 = 2 x 6 =3x + 9 = 12. Now, combine like terms. ...3x + 9 - 9 = 12 - 9 =3x = 3.
Isolate the variable, x, by dividing both sides by 3 and you've got your answer.3x/3 =
3/3 =x =1.
How do you solve a problem algebraically?
Two step equation: 2x + 1 = 7 Subtract 1 on both sides and then divide by 2. Multi-step equation: 2x – 5 + 6x = 6x + 7 Combine 'like' terms on the same side of the equation, then add to and subtract to get x's on one side of the equation and numbers on the other. In the final step, divide to find out what x equals.
(x + 3)/6 = 2/3. First, cross multiply to get rid of the fraction. ...(x + 3) x 3 = 2 x 6 =3x + 9 = 12. Now, combine like terms. ...3x + 9 - 9 = 12 - 9 =3x = 3.
Isolate the variable, x, by dividing both sides by 3 and you've got your answer.3x/3 =
3/3 =x =1.
How do you solve a problem algebraically?
Two step equation: 2x + 1 = 7 Subtract 1 on both sides and then divide by 2. Multi-step equation: 2x – 5 + 6x = 6x + 7 Combine 'like' terms on the same side of the equation, then add to and subtract to get x's on one side of the equation and numbers on the other. In the final step, divide to find out what x equals.
niya25:
thanks .... I took that from my book
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