Question

how to solve an algebric equation if there is square root in denominator

Answer 1

Multiply and divide the denominator square root in numerator as well as denominator.

for exampe 1/root 2 = 1/root 2 *root 2/ Root 2

hope u understand

Answer 2

Let me explain by taking two different examples

1. $\frac{5}{\sqrt2}$

Rationalize i.e multiply numerator and denominator by √2.

=$\frac{5}{\sqrt2}\times\frac{\sqrt2}{\sqrt2}=\frac{5\sqrt{2}}{2}$

This is the way when there is single number in the denominator having square root.

2. if the algebraic equation is like this

$\frac{1}{\sqrt{3}+\sqrt{2}}</p><p>=\frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}}\times{\frac{1}{\sqrt{3}-\sqrt{2}}</p><p>={\sqrt{3}-\sqrt{2}}$     [(a+b))(a-b)=a² -b²=(√3)² -(√2)²=3-2=1

This is second type when there is denominator having square root.