Question

how to solve and what is the answer??​

Answer 1

Answer:

$\frac{4 {x}^{2} - 8x + 12}{x - 3} \\ \\ = \frac{4( {x}^{2} - 2x + 3) }{x - 3} \\ \\ = \frac{ {x}^{2} - 2x + 3 }{x - 3} \\ \\ = \frac{ {x}^{2} - (3 - 1)x + 3 }{x - 3} \\ \\ = \frac{ {x}^{2} - 3x + x + 3 }{x - 3} \\ \\ = \frac{x(x - 3) + ( x - 3)}{x - 3} \\ \\ = \frac{(x - 3)(x + 1)}{(x - 3)} \\ \\ = x + 1$

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Answer 2

Answer:

x+1 is the correct answer hope you get it no explanation