Question

how to solve (b) part​

Answer 1

Answer:

$p = \frac{7}{2} = 3\frac{1}{2}$

$p = \frac{7}{4} = 1\frac{3}{4}$  The change is that, it gets halved.

Step-by-step explanation:

Q37 (ii)  A(7, 0) and C(0, 2)

Z = px + y  . . . . . . . . . . . . . . . . . (i)

Z(A) = Z(C)

=> p . 7 + 0 = p . 0 + 2

=> 7p = 2

∴ $p = \frac{7}{2} = 3\frac{1}{2}$

Z(A) = 2Z(C)

=> p . 7 + 0 = 2(p . 0 + 2) = 4

=> 7p = 4

∴ $p = \frac{7}{4} = 1\frac{3}{4}$

∴ The change is that, it gets halved.