Chemistry, asked by sonkamblemilind01, 3 months ago

how to solve Bef2 is hybridization theory​

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Answered by Anonymous
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BeF2 molecule

Beryllium atom has the configuration 1s2, 2s2. Since there are no unpaired electrons in the valency shell, it cannot form any covalent bond. Thus, 2s-orbital is first unpaired and an electron is shifted to 2p-orbital. Now, there is hybridization between one s-and one p orbital.

Answered by Anonymous
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