Question

how to solve double square root surds √27-10√2

Answer 1

√(27 - 10√2)  = 5 - √2

Step-by-step explanation:

$\sqrt{27 - 10\sqrt{2} } \\ \\=\sqrt{25 + 2 - 10\sqrt{2} } \\= \sqrt{5^{2} + (\sqrt{2}) ^{2} - 2\times5\times\sqrt{2} }$

now applying (a - b)² = (a² + b² - 2ab)

a = 5

b = √2

$= \sqrt{(5 - \sqrt{2}) ^{2} } \\ \\= 5 - \sqrt{2}$

√(27 - 10√2)  = 5 - √2

Learn more:

find the square root of(1+i)2 - Brainly.in

https://brainly.in/question/8014848

If x = square root of (m+n)+square root of (m-n)/square root of (m+n ...

https://brainly.in/question/9576987