Math, asked by sahusrinivas4358, 1 month ago

how to solve elimination method​

Answers

Answered by Anonymous
0

Answer:

The Elimination Method

Step 1: Multiply each equation by a suitable number so that the two equations have the same leading coefficient. ...

Step 2: Subtract the second equation from the first.

Step 3: Solve this new equation for y.

Step 4: Substitute y = 2 into either Equation 1 or Equation 2 above and solve for x.

Answered by sahoobibhu1998
0

Step-by-step explanation:

MathsFirst Home

Example !!!!!

Equation 1: 2x + 3y = 8

Equation 2: 3x + 2y = 7

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Step 1: Multiply each equation by a suitable number so that the two equations have the same leading coefficient. An easy choice is to multiply Equation 1 by 3, the coefficient of x in Equation 2, and multiply Equation 2 by 2, the x coefficient in Equation 1:

3 * (Eqn 1) --->

3* (2x + 3y = 8)

---> 6x + 9y = 24

2 * (Eqn 2) --->

2 * (3x + 2y = 7)

---> 6x + 4y = 14 Both equations now have the same leading coefficient = 6

Step 2: Subtract the second equation from the first.

-(6x + 9y = 24

-(6x + 4y = 14)

5y = 10

Step 3: Solve this new equation for y.

y = 10/5 = 2

Step 4: Substitute y = 2 into either Equation 1 or Equation 2 above and solve for x. We'll use Equation 1.

2x + 3(2) = 8

2x + 6 = 8 Subtract 6 from both sides

2x = 2 Divide both sides by 2

x = 1

Solution: x = 1, y = 2 or (1,2).

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