Chemistry, asked by rohanlalyadav, 1 year ago

how to solve equatin KMnO4+FeSO4+H2SO4=K2SO4+MnSO4+Fe(SO4)3+H2O

Answers

Answered by shrikant7

2 KMnO4 + 10 FeSO4 + 8 H2SO4 = 2 MnSO4 + 5 Fe2(SO4)3 + K2SO4 + 8 H2O

2 KMnO4 + 3 H2SO4 = K2SO4 + 2 MnSO4 + 6 H + 8 O

10 FeSO4 + 5 H2SO4 = 5 Fe2(SO4)3 + 10 H
6 H + 8 O + 10 H = 8 H2O

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