Question

how to solve equation 2y-x=0;10x+15y=22

Answer 1

2y-x=0

x-2y=0..........................1

10x+15y=22................2

...................................................................................................................................................

10x-20y=0................1x10

-10x-15y=-22..............2x-

add both

35y=22

y=22/35

sub in 1

x-2[22/35]=0

x-44/35=0

x=44/35

∴$x=\frac{44}{35} ,y=\frac{22}{35}$

Answer 2

Hey mate!!!
$<b>Here is your answer </b>$

We know that ;

$2y - x = 0$_eq1
And also,
$10x + 15y = 22$_eq2

Now,
By Eq1 * 10,
We get ;
$20y - 10x = 0$_eq3

Adding eq2 and eq3,
We get ;
$10x - 10x + 15y + 20y = 22$
=> $35y = 22$
=> $y = \frac{22}{35}$

Therefore,
From eq1
We get;
=> $x = \frac{44}{35}$

$<b><big><marquee>Hope it helps you...$