how to solve equation 3x+4y=5 and 4x+3y=6
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For solving these equations-
simply subtract both of them but remember you have to first terminate or vanish one variable,for that first you have to make one of the coefficient same.
for eg- by multiplying eq1. (3x+4y=5) by 4
it will become 12x + 16y = 20
And Multiply eq2. (4x + 3y =6) by 3
it will become 12x + 9y = 18
Now Subtract both of them or this is also called Elimination method.
12x + 16y = 20
12x + 9y = 18
0 + 7y = 2. , y= 2/7
Now put this value of y=2/7 in any of the equation in your question.
3x+ 4(2/7) = 5
3x+ 8/7 = 5
3x=5- (8/7)
3x=35-8/7
3x=27/7
x =27/21 =9/7
x=9/7.
y=2/7 so this is your solution.
simply subtract both of them but remember you have to first terminate or vanish one variable,for that first you have to make one of the coefficient same.
for eg- by multiplying eq1. (3x+4y=5) by 4
it will become 12x + 16y = 20
And Multiply eq2. (4x + 3y =6) by 3
it will become 12x + 9y = 18
Now Subtract both of them or this is also called Elimination method.
12x + 16y = 20
12x + 9y = 18
0 + 7y = 2. , y= 2/7
Now put this value of y=2/7 in any of the equation in your question.
3x+ 4(2/7) = 5
3x+ 8/7 = 5
3x=5- (8/7)
3x=35-8/7
3x=27/7
x =27/21 =9/7
x=9/7.
y=2/7 so this is your solution.
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