Question

How to solve f(x) =2x³-5x²-3(x) and g(x) =(x⁴-27x)

Answer 1

Answer:

Hope that it is helpful

Step-by-step explanation:

f(x)=40x(2x2−5x−3)=40x(2x2−6x+x−3)=40x(2x(x−3)+1(x−3))=40x(2x+1)(x−3)=2×2×2×5x(2x+1)(x−3)g(x)=35(x4−27x)=35x(x3−27)=35x(x3−33)=35x(x−3)(x2−3x+9)=5×7×x(x−3)(x2−3x+9)sohcfis=5x(x−3)lcm=23×5×7×x(2x+1)(x−3)(x2−3x+9)=280x(2x+1)(x−3)(x2−3x+9)