how to solve I can't solve that question
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hey
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given: ABCD is a || gm where AD is produced to E and BE is cuts CD at F
to proove : ∆ABE is congruent to ∆BFC
proof : in ∆ABE and ∆BFC
AD = BC ( opposite sides of ||gm are equal )
then , AE = BC ...........(1)
<A = <C ( opposite angles of ||gm are equal )...(2)
as we know that opposite sides of a || gm are parallel
AD ||BC
then , DE ||BC and BE is the transversal
< 1 = <2 ( by alternate interior angles ).......(3)
in ∆ABE and ∆BFC
_______________
<A = <C ( from (2) )
BC = AE ( from (1) )
<1 = <2 ( from (3) )
hence, ∆ABE is similar to ∆BFC by ASA criteria
for the figure, refer to the attachment
hope helped
____________
____
given: ABCD is a || gm where AD is produced to E and BE is cuts CD at F
to proove : ∆ABE is congruent to ∆BFC
proof : in ∆ABE and ∆BFC
AD = BC ( opposite sides of ||gm are equal )
then , AE = BC ...........(1)
<A = <C ( opposite angles of ||gm are equal )...(2)
as we know that opposite sides of a || gm are parallel
AD ||BC
then , DE ||BC and BE is the transversal
< 1 = <2 ( by alternate interior angles ).......(3)
in ∆ABE and ∆BFC
_______________
<A = <C ( from (2) )
BC = AE ( from (1) )
<1 = <2 ( from (3) )
hence, ∆ABE is similar to ∆BFC by ASA criteria
for the figure, refer to the attachment
hope helped
____________
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