How to solve it..............
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hope it will help you
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given ,
sec(5A) =cosec(A-36)
but we know sectheta =cosec [90-theta]
from that,
cosec[90-5A]=cosec[A-36]
90-5A=A-36
126=6A
21°=A
I HOPE THIS WILL HELP U
sec(5A) =cosec(A-36)
but we know sectheta =cosec [90-theta]
from that,
cosec[90-5A]=cosec[A-36]
90-5A=A-36
126=6A
21°=A
I HOPE THIS WILL HELP U
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