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abhinav4254:
a bit faster please...first will be marked brainliest
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2.5 l of alchol should be more added to contain 90% alcohol
volume of solution =50l
volume %=85%
volume %= (volume of solvent÷volume of solution)*100
85=(volume of solvent÷50)*100
volume of solvent(v1) 85÷2=42.5l
volume%=90%
90=(volume of solvent÷50)*100
volume of solvent (v2)90÷2=45
alchol must be added=v2-v1
45-42.5=2.5l
volume of solution =50l
volume %=85%
volume %= (volume of solvent÷volume of solution)*100
85=(volume of solvent÷50)*100
volume of solvent(v1) 85÷2=42.5l
volume%=90%
90=(volume of solvent÷50)*100
volume of solvent (v2)90÷2=45
alchol must be added=v2-v1
45-42.5=2.5l
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