how to solve it?????
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TonyGujjar:
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hypotenuse of right angled triangle=p
it's one side=q
let the another side be x
by Pythagoras theorem
x=√p2-q2
= √(p+q) (p-q)
but p-q=1
=√(p+q) 1
=√p+q
the another side of triangle is √p+q
I hope this will help you
it's one side=q
let the another side be x
by Pythagoras theorem
x=√p2-q2
= √(p+q) (p-q)
but p-q=1
=√(p+q) 1
=√p+q
the another side of triangle is √p+q
I hope this will help you
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