Question

how to solve it.. can anyone plz help me....​

Answer 1

Answer:

Step-by-step explanation:

Given chord length (PQ) = 16cm,

Radius (OP) = 10cm

Tangent (PT) = ?

i) PR = RQ = PQ/2 = 8cm

/* The perpendicular from the centre of a circle to a chord bisects the chord */

ii) In right triangle ORP,

<ORP = 90°,

By Phythagorean theorem:

OR² = OP² - PR²

= 10² - 8²

= 100 - 64

= 36

=> OR = 6 cm,

iii ) Let TR = x , PT = y

In ∆OPR and ∆OPT,

<POR = <POT

<PRO = <OPT = 90°

∆OPR ~ ∆OPT (AA similarity)

PT/PR=OP/OR

Y/8=10/6

Y=40/3 CM

.: TP=40/3 CM

Therefore,

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