how to solve it
in brief very easy method
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so easy just put the formula
a^2+b^2=(a+b)^2 - ab just put x+y and xy
a^2+b^2=(a+b)^2 - ab just put x+y and xy
Answered by
1
it's pretty simple,
(x+y)² = x² + 2xy + y²,
now we can write it as, x²+y² = (x+y)²-2xy,
(1) Given that x+y = 12, and xy = 32, x²+y² = ?,
Substitute those values in the above formula,
=> x²+y² = 12² - 64 = 144-64 = 80,
Now,
(2) x - 1/x = 6, Square the terms on both the sides,
=> (x - 1/x)² = 36,
=> x² + 1/x² -2(x)(1/x) = 36,
=> x² + 1/x² - 2 = 36,
=> x² + 1/x² = 38,
Therefore we got the both answers, and see it's pretty simple, The first problem answer is 80 and second problem answer is 38,
Hope you understand, Have a great day !
(x+y)² = x² + 2xy + y²,
now we can write it as, x²+y² = (x+y)²-2xy,
(1) Given that x+y = 12, and xy = 32, x²+y² = ?,
Substitute those values in the above formula,
=> x²+y² = 12² - 64 = 144-64 = 80,
Now,
(2) x - 1/x = 6, Square the terms on both the sides,
=> (x - 1/x)² = 36,
=> x² + 1/x² -2(x)(1/x) = 36,
=> x² + 1/x² - 2 = 36,
=> x² + 1/x² = 38,
Therefore we got the both answers, and see it's pretty simple, The first problem answer is 80 and second problem answer is 38,
Hope you understand, Have a great day !
zeenatshah:
thank u
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