Question

how to solve it please solve it​

Answer 1

Answer:

In f(2x+3y,2x−7y)=20x

Let 2x+3y=X ...(1)

and 2x−7y=Y ...(2)

Multiplying (1) by 7 and (2) by (3) we get

14x+21y=7X and 6x−21y=3Y

Adding them

20x=7X+3Y

Hence

f(X,Y)=7X+3Y

or f(x,y)=7x+3y

Answer 2

Answer:

Given y = 2^cosx^2

Taking log both side

Logy =cos square x×log2

Differentiate both side with respect to x

dy/ydx = log2(2cosx × sinx) + 0(because log2 is constant)

dy/dX = (sin2x × log2)/y. Put the value of y

dy/dX = (sin2x× log2)/(2^2cos square x)

dy/dx = (sin2x × log2) (2^-2cos square x)