Question

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Answer 1

Answer:

here BC parallel to AD

so BA transversal

y=angle BAD(Alternate angle)

so y=55°

BA is the common line

BC and AC lie on ends of BA

BC=AC

so y=angle BAC

angle BAC=55°

y+x+angle BAC=180°

55+x+55=180

110+x=180

x=180-110

x=70°

Step-by-step explanation:

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