how to solve length 20 cm and breath 48 cm it's perimeter and area both
Answers
Answered by
2
perimeter=
![= 2(l + b) \\ 2 \times 20 + 48 \\ 2 \times 68 \\ 13 = 2(l + b) \\ 2 \times 20 + 48 \\ 2 \times 68 \\ 13](https://tex.z-dn.net/?f=+%3D+2%28l+%2B+b%29+%5C%5C+2+%5Ctimes+20+++%2B++48+%5C%5C+2+%5Ctimes+68+%5C%5C+13)
area,=
![l \times b \\ \: 20 \times 48 \\ 960 l \times b \\ \: 20 \times 48 \\ 960](https://tex.z-dn.net/?f=l+%5Ctimes+b+%5C%5C+%5C%3A+20+%5Ctimes+48+%5C%5C+960)
area,=
Answered by
0
to solve perimeter we have to
2(length+breath)= 2(20+48)
so answer is 34
to solve area we have to
length×breath
so answer is 960
2(length+breath)= 2(20+48)
so answer is 34
to solve area we have to
length×breath
so answer is 960
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