Math, asked by ajju98, 11 months ago

how to solve
log(2×10^13))=?

please answer me fast i will mark u brailist..​

Answers

Answered by AseemSinghKhuranna
7

Answer:

Log (2 x 10¹³)

= log2 + log 10¹³

= log2 + 13log10

= log2 + 13(1) .....( log10 = 1 )

= 13 + log2

I hope this is helpful

Answered by sadiaanam
0

Answer:

The answer of this given problem is:-

log(2*10¹³)=13.303

Step-by-step explanation:

From the given data of this question we have got that:-

The problem is:- log(2*10¹³)

Now we have to solve this,the solution is given below:-

log(2*10¹³)= log2 + log 10¹³[log(a*b)= loga + logb]

= log2 + 13 log10

= log2 + 13[log10= 1]

= 0.303+ 13[log2= 0.303]

= 13.303

This is the required solution for this question.

The answer of the problem is;

log(2*10¹³)=13.303

Now we have to know about logarithm.

Logarithm:-

A base must be raised to a certain exponent or power, or logarithm, in order to produce a specific number. If

 {b}^{x}  = n \\ then \: x =   log  \binom{b}{n}

To know more about Logarithm visit this link:-

https://brainly.in/question/41400643

#SPJ3

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